Java Program to check whether a number is Armstrong Number

What is Armstrong Number ?

In an Armstrong Number, the sum of power of individual digits is equal to number itself.

In other words the following equation will hold true

xy..z = xn + yn+.....+ zn

n is number of digits in number

For example this is a 3 digit Armstrong number

370 = 33 + 73 + 03
    = 27 + 343 + 0
    = 370

Examples of Armstrong Numbers

0, 1, 4, 5, 9, 153, 371, 407, 8208, etc.
Program:
public class ArmstrongNumber 
{
 public static void main(String[] args) 
 {
   int inputArmstrongNumber = 153; //Input number to check armstrong  
   int tempNumber, digit, digitCubeSum = 0;
         tempNumber = inputArmstrongNumber;
         while (tempNumber != 0)
         {
         /* On each iteration, remainder is powered by thetempNumber of digits n
           */
             System.out.println("Current Number is "+tempNumber);
             digit =tempNumber % 10;
    System.out.println("Current Digit is "+digit);
             //sum of cubes of each digits is equal to thetempNumber itself
             digitCubeSum = digitCubeSum + digit*digit*digit;
    System.out.println("Current digitCubeSum is "+digitCubeSum);
             tempNumber /= 10;
         }
         //check giventempNumber and digitCubeSum is equal to or not 
         if(digitCubeSum == inputArmstrongNumber)
             System.out.println(inputArmstrongNumber + " is an Armstrong Number");
         else
             System.out.println(inputArmstrongNumber + " is not an Armstrong Number");
  }
 }

Output:

Current Number is 153
Current Digit is 3
Current digitCubeSum is 27
Current Number is 15
Current Digit is 5
Current digitCubeSum is 152
Current Number is 1
Current Digit is 1
Current digitCubeSum is 153
153 is an Armstrong Number